- English

English

- English
- Deutsch
- Français
- Italiano

Author：PoolClub
Click：
Time：2022-04-27 10:30:45

Two days ago, we received a consultation from a customer. He built a swimming pool in the yard, which is 7 meters long, 4 meters wide, 1.5 meters high, and about 42 cubic meters. In order to increase the use of the swimming pool, he considered buying a swimming pool heating system. The question is should you buy an electric heater or an INVERPAC air energy pool heat pump?

Let's do some calculations first and look at the energy consumption of the pool. The temperature maintenance of the swimming pool is usually divided into two stages. The first stage is heating, which heats the swimming pool water temperature to the target temperature; the second stage is constant temperature, which maintains the swimming pool water at the target water temperature.

The customer said that the swimming pool heat pump is mainly used in spring and autumn. The weather temperature and water temperature are assumed to be 15℃, and how much should the swimming pool water temperature be maintained? Calculated according to the international standard at 28℃.

Let’s first calculate the swimming pool heating stage, from 15℃ to 28 ℃, a total of 13℃ of water temperature needs to be raised.

It takes 4190 kj to raise 1 cubic degree of water by 1 degree Celsius, or 1.16KWH.

To raise 42 cubic meters of pool water by 13℃, the heat required is:

1.16KWH X 13 X42 = 633.36KWH

According to the recommendations of the International Swimming Pool Association, the heating of the swimming pool should preferably be completed within 48 hours. Every day, the water temperature of the swimming pool will be affected by various factors and will be lost, such as wind speed, whether there is a pool cover, whether the swimming pool is insulated, the heat transfer of the water, etc. Let’s calculate it at a daily loss of 12%.

Then the total heat required to heat from 15℃ to 28℃ in 2 days is:

633.36KWH X (1+12%+12%)=785.37 KWH

2 days is 48 hours, that is, the energy cost required per hour:

785.37KWH / 48 = 16.36KWH

That is, the customer only needs a swimming pool heating system with a heat output of not less than 16.36KWH per hour to meet his needs.

With traditional electric heating, 20% of the electricity loss is considerable. If it needs to generate no less than 16.36KWH of heat per hour, it needs to consume 20KWH per hour.

If the customer chooses the pool heat pump of INVERPAC Turbo 25. How much will that save? In fact, looking at the swimming pool heat pump, in addition to the workmanship, the accessories, and the feeling of use, the most important thing is the COP of the swimming pool heat pump. COP refers to the ratio of the heating capacity to the power consumption. The operating principle of the swimming pool heat pump is to absorb heat from the air, and then transfer it to the water, so as to heat the swimming pool, and the swimming pool heat pump needs electricity to start, consumes 1KWH of electricity, and can generate 5KWH of heat, then the COP is 5, so The higher COP, the more heat is produced under the same consumption, and the more energy-saving it is.

The heat pump of INVERPAC Turbo series has a COP of 5.52 when the water temperature is 15℃ and the ambient temperature is 15℃. If we choose INVERPAC TURBO 25, in TURBO mode, it can generate 18KWH of heat per hour, and in this case, The COP of INVERPAC TURBO 25 is about 5.5, that is, for every 1KWH of electricity consumed, 5.5KWH heat can be produced, and the output of 16.36KWH is only required 3KWH of electricity, which is far lower than the 20KWH of the electric heater.

Just heat for 2 days (48 hours) and save energy with the INVERPAC TURBO 25 pool heat pump

(20-3KWH)*48hours= 816KWH

What is the electricity cost in your city? Can you calculate how much electricity you can save in just 2 days?

Online

- WhatsApp Service
- Cancel